![wolframalpha - Wolfram alpha is able to integrate an indefinite integral but not a definite integral of the same function? - Stack Overflow wolframalpha - Wolfram alpha is able to integrate an indefinite integral but not a definite integral of the same function? - Stack Overflow](https://i.stack.imgur.com/9vVDT.png)
wolframalpha - Wolfram alpha is able to integrate an indefinite integral but not a definite integral of the same function? - Stack Overflow
![SOLVED: For the wavefunction = 2axe^(-ax) for x > 0 and = 0 for x < 0. Hint for a-c: Use Wolfram-Alpha Definite Integral Calculator. Show that P = 0. [Link to SOLVED: For the wavefunction = 2axe^(-ax) for x > 0 and = 0 for x < 0. Hint for a-c: Use Wolfram-Alpha Definite Integral Calculator. Show that P = 0. [Link to](https://cdn.numerade.com/ask_images/6db5496a633c4bbe94012e528bcda8d0.jpg)
SOLVED: For the wavefunction = 2axe^(-ax) for x > 0 and = 0 for x < 0. Hint for a-c: Use Wolfram-Alpha Definite Integral Calculator. Show that P = 0. [Link to
![definite integrals - Why can't Wolfram Alpha calculate $\int_0^{2\pi}\sqrt{(a-\cos\theta)^2+\sin^2\theta}\ d\theta$? - Mathematics Stack Exchange definite integrals - Why can't Wolfram Alpha calculate $\int_0^{2\pi}\sqrt{(a-\cos\theta)^2+\sin^2\theta}\ d\theta$? - Mathematics Stack Exchange](https://i.stack.imgur.com/ws7CG.png)